I don’t know if my mind is wasting time, whether it’s a pipe dream or whether it’s worth a look. I struggle to think clearly and I’ve not had the energy to study. Despite wasting most of my life learning about code, at the moment, today, I can’t do it…

I can’t sleep. I thought I’d indulge in talking to myself on this thing. I can’t imagine it’s remotely interesting to anybody else, and frankly I have a tendency to be more honest than anybody should be given that anybody could read this. Still, I find it theraputic, if you…

I am so tired. I probably start most of my posts like that. I’ve slept all day and a good chunk of the night but I got bored. MK1 was crashing and so I thought I’d have a go at this. What is the square root of anything? Is it…

At the risk of offending readers, and I know I have many of them, but I made a joke I shouldn’t have and I won’t repeat it. Well, less a joke and more a shock humour remark and it went down very badly with a very good friend of mine…

Simple idea, take two binary string values, add the pair o bastards together and see whatcha get! Return a new string. I don’t think this needs to be done by hand. Which is good as I’m tired. I remember…vaguely adding binary numbers in college. Two’s complement…but I’ve got a feeling…

Okay, so we get an array of numbers. I don’t know what the rest of what it says means, I think it’s just saying it’s a decimal number split into an array. This is fine. Increment the large integer by one and return the array of digits. This should be…

I’m thinking trim the left and right sides of the string, then call split with the delimiter being spaces, grab the last element, find its length, Bob’s your uncle.

This doesn’t look too complicated. I won’t do it now though. I got sleeping to do. Searching for the number should be easy. If it’s not found then it’ll be number comparisons and edge cases like empty arrays or finding it’s position if the array’s not empty. Which isn’t so…

This one will need me to look up how it’s done in JavaScript, but I don’t think this is going to be particularly difficult with the string functions given to you by JS. In fact it looks like there’s a function that already does exactly what’s needed. It’s called search()…